CIVE 461/861: Urban Transportation Planning
Total number of trips generated in a TAZ based on zone properties: population, employment, number of cars, etc. (method: regression)
Trip frequency choice by households (method: discrete choice)
Generally recognized that travel decisions are not actually taken in this type of sequence
Model sequencing depends on the form of the utility function assumed to govern all these travel choices
Four-stage model is seen as concentrating attention on only a limited range of travellers’ responses
Number of employees
Number of sales
Roofed area of firm
Total area of firm
What about type of firm? Accessibility? Curiously, few applications in freight models despite it seeming logical that different products have different transport requirements
A1 ×Population in Downtown Area
+ A2×Population in Inner Suburbs
+ A3×Population in Outer Suburbs
Consider the variables trips per household (\(Y\)), number of workers (\(𝑋_1\)), and number of vehicles (\(𝑋_2\)). Successive steps were performed of a stepwise model estimation. Values (in parenthesis) are t-ratios. In the step 4 model, \(Z_1\) takes the value 1 for households with one car and 0 otherwise and \(Z_2\) takes the value 1 for households with two or more cars and 0 otherwise. We can see that zero car households will have the value 0 for both \(Z_1\) and \(Z_2\). Even without the higher \(R^2\), the step 4 model would be preferred because it clearly demonstrates there is a non-linear effect that’s ignored by \(𝑋_2\).
Models do not guarantee, by default, that total trips originating in a zone (the origins O_𝑖) at all zones will equal the total trips attracted (the destinations 𝐷_𝑗)
Following expression may not hold \[\sum_i O_i=\sum_j D_j\]
Generally assumed that trip generation models are better than trip attraction models
Total trips are then \(T=\sum_i O_i\) & a factor applied to trip attraction \[f=T/\sum_j D_j\]
This equality is necessary for the next model step: trip distribution
Consider a zone with 250 households with vehicles and 250 households without vehicles. Assuming we know the average trip generation rates of each group:
We can determine the current number of trips as \[T_i = 250 \times 2.5 + 250 \times 6.0 = 2125 \text{ trips/day}\]
Let’s assume that all households in the future have a vehicle. We can then estimate a simple multiplicative growth factor as \[F_t = 1/0.5 = 2.0\] \[T_{i+t} = 2 \times 2125 = 4250 \text{ trips/day}\]
Growth factor methods are crude & generally used in practice for external trips where additional information is not available
\[T_i = 6 \times 500 = 3000 \text{ trips/day}\]